解log3(2)-log2(3/2)=log3(2)-log2(3)+log2(2)=log3(2)+1-log2(3)=log3(6)-log2(3)注意到log3(6)＞log3(3)^(3/2)=log3(√27)而log2(3)＜log2(2^(3/2))=log2(√8)故log3(6)-log2(3)＞0故log3(2)＞log2(3/2)
先选一个参照数比如1，再分别将它们与1比较就行了
